The length of a new rectangular playing field is 8 yards longer than double the width. if the perimeter of the rectangular playing field is 280 yards, what are its dimensions.

Let

width,w

length, l = 2w +8...eqn 1

perimeter, p = 2 (l + w)...eqn 2

subst for l in eqn 2...

p = 2(2w +8 + w) = 2 (3w + 8) = 280

280 = 6w + 16

w = 264 /6 = 44

subst for w in eqn 1

l = 2× 44 + 8 = 96

length = 96yds

width = 44 yds

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!