There are three consecutive even numbers such that twice the first is 20 more than the second. find the number

Step-by-step explanation:

2n is an even number.

Your three even numbers are 2n, 2n + 2, 2n + 4

Twice the first is 20 more than the second.

2n * 2 = 2n + 2 + 20

Simplify:

4n = 2n + 22

Use simultaneous equations to solve n.

4n = 2n + 22 - 2n

2n = 22 ÷ 2

n = 11

Subsitiye n into the three even numbers.

2n, 2n + 2, 2n + 4

2 * 11, 2 * 11 + 2, 2 * 11 + 4

22, 24, 26

Check that the numbers meet the requirements.

22 * 2 = 24 +20

44 = 44

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|