Leave answer in exact form unless otherwise indicated.

find the area of a segment formed by a chord 8" long in a circle with radius of 8".

Area segment = 32/3 π - 16√3 inches²

Step-by-step explanation:

∵ The length of the chord is 8"

∵ The length of the radius of the circle is 8"

∴ the central angle of the segment is π/3 (60° the chord and the radii

   formed an equilateral triangle)

∵ The area of the segment = area the sector - area Δ

∵ Area sector = 1/2 r²Ф

∵ r = 8" and Ф = π/3

∴ Area sector = 1/2 (8²) (π/3) = 32/3 π inches²

∵ Area Δ = 1/4 s²√3

∵ The length of the side is 8"

∴ Area Δ = 1/4 (8²) √3 = 16√3 inches²

∴ Area segment = 32/3 π - 16√3 inches²

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: