In right triangle qrs, angle r is a right angle. the altitude rt is drawn to hypotenuse qs. if qr is 20 and qs is 25 then find the length of qt.

length of qt = 16

Step-by-step explanation:

Given in the question that qrs is a right angle triangle,

where qr = 20

          sr = ?

          qs = 25

          qt = ?

hypotenuse² = base² + height²

sq² = sr² + rq²

25² - 20² = sr²

sr = √25² - 20²

sr = 15

2)

When altitude rt is drawn to hypotenuse qs, it divides the triangle qrs into

two right angle triangle, rtq and rts.

Δrtq

height = rt

base= tq = 25 - x

hypotenuse = qt = 20

Δrts

height = rt

base= ts = x

hypotenuse = sr = 15

These both triangle shares same altitude that is rt

So, by using pythagorus theorem

      Δ rtq                                               Δ rts

hypotenuse² - base² = height² = hypotenuse² - base²

20² - (25 - x)² = 15² - x²

400 - (625 + x² - 50x) = 225 - x²

400 - 625 - x² + 50x = 225 - x²

-225 - x² + 50x - 225 + x² = 0

-450 + 50 x = 0

50x = 450

x = 450/50

x = 9

base of Δ rtq = tq = 25 - x

                         tq = 25 - 9

                         tq = 16  

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

its a straight line parallel to the time axis