Write an equation of the circle given its center and radius

y = x²- 4x + 3 + y²

The equation of a circle is given by the formula

(x-a)²+(x-b)² = r²

Where;  (a, b) is the center of the circle and r is the radius

Center (2,0) and radius = 1.

Therefore:

(x-2)² +(y+0) = 1²

x²- 4x + 4 + y² =  1

x²- 4x + 3 + y² =  0

Therefore; The equation of the circle is y = x²- 4x + 3 + y²

(x-2)²+ y² = 1 is the equation of given  circle.

Step-by-step explanation:

We have given the center (2,0) and radius  r = 1 of a circle.

We have to find the equation of circle.

As we know the equation of circle is :

(x - x₁)² +(y - y₁)² = r²    

Where (x₁,y₁) is the center of circle, and r is the radius of the circle.

Putting the value in above equation we get,

(x-2)²+(y-0)² = 1²

(x-2)²+ y² = 1 is the equation of given  circle.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743