Nadine walked 1/4 of a mile, janet walked 3/8 of a mile, and perry walked 5/6 of a mile. who walked the farthest? how much farther did perry walk than nadine?

Perry walked farthest.

Perry walked 0.6 miles farther than Nadine.

Step-by-step explanation:

Divide the numerator by the denominator of each distance. Then:

Nadine:

Janet:

Perry:

Threfore Perry walked farthest.

Now, you must subtract the distance Perry walked and  the distance Nadine walked:

Therefore, Perry walked 0.6 miles farther than Nadine.

1). Perry is farthest.

2).  Perry walk 7/12 of a mile farther than Nadine

Step-by-step explanation:

It is given that,Nadine walked 1/4 of a mile, Janet walked 3/8 of a mile, and Perry walked 5/6 of a mile.

Nadine  - 1/4

Janet - 3/8

Perry - 5/6

To find the LCM of 4,6,8

LCM(4, 6, 8) = 24

To find who is farthest

1/4 = 6/24 (Nadine )

3/8 = 9/24 (Janet )

5/6 = 20/24 (Perry )

6/24 < 9/24 < 20/24

Therefore Perry is farthest.

Perry walk 20/24 and Nadine walk 6/24

Difference = 20/24 - 6/24 = 14/24 = 7/12

Therefore Perry walk 7/12 of a mile farther than Nadine

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.

i need more details sorry

step-by-step explanation: