The width of a photo is 5 inches less than its length. a border of 2 inches is placed around the photo. the area covered by the photo and its border is 104 square inches. find the dimensions of the photo itself

Dimensions of photo excluding border:

x = 11 inches

y = 6 inches

Step-by-step explanation:

Let the length be 'x' and width be 'y'.

The width of a photo is 5 inches less than its length, that is:

x-5 = y

let 'X' be length of photo including border and 'Y' be the width of photo including border:

Where X = x+2 and Y = y+2

Now , we have X-5 = Y

and X*Y = 104 square inches

*putting Y = X-5*

X(X-5) = 104

⇒ X-13 = 0          or        X+8 = 0

Hence X = 13       or X = -8

As length can not be negative, X = 13 inches

Y = X-5 = 13-5 = 8 inches

Dimensions of photo excluding border:

x = X - 2 = 13-2 = 11 inches

y = Y-2   =  8-2 =  6 inches

there will be 35 boys in each team. : )

details

step-by-step explanation: