Mathematics, 30.01.2020 16:54 jadeandryna0609

2step word problem practice how do you explain 2 step work problem to a 2nd grader

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Step 1: identify the constant on the side of the equal sign that has the variable term. Subtract that constant from both sides of the equation.Step 2: identify the coefficient of the variable. Divide both sides of the equation by that coefficient.

Step-by-step explanation:

Example:

2x + 3 = 7

Step 1. The variable term (containing x) is on the left. The constant term on the left side of the equal sign is +3. We add the opposite of that to both sides of the equation:

2x +3 -3 = 7 -3 . . . . . showing -3 being added (or 3 being subtracted)

2x = 4 . . . . . . . . . . . . result of carrying out the addition/subtraction

Step 2. The variable term (on the left) has 2 as its coefficient. We divide both sides of the equation by 2 (or, equivalently, multiply by the reciprocal of 2: 1/2).

2x/2 = 4/2 . . . . . . . . showing both sides of the equation being divided by 2

x = 2 . . . . . . . . . . . . . result of carrying out the division

The solution is x=2.

The problems I expect to see presented to a 2nd grader will have a "blank" instead of a variable. In that case, one would first solve the addition/subtraction problem to identify the value of the term containing the "blank". That is, the above would look like ...

2×___ + 3 = 7

This is effectively equivalent to ...

_._._ + 3 = 7 . . . . . . . . we're using _._._ to stand for 2×___

Most 2nd graders can solve this because they are familiar with their addition facts. So, they would know ...

_._._ = 4 . . . . . . or . . . . 4 + 3 = 7 . . . . . (4 goes in the _._._ blank)

Now, the second step is to solve the multiplication equation ...

2×___ = 4

When I was in 2nd grade, we hadn't learned multiplication facts, so this would not be a problem we would be expected to solve. If your second grader knows multiplication facts, then they know ...

2 × 2 = 4

so 2 goes in the blank.

Answer from: Quest

step-by-step explanation:

Answer from: Quest

x² + 3x + 7 = 0 [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

$x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}$ (+/- is this ±)

plug in the numbers into the variables

$x = \frac{-3+/-\sqrt{3^2-4(1)(7)} }{2(1)}$

$x=\frac{-3+/-\sqrt{9-28} }{2}$

$x=\frac{-3+/-\sqrt{-19} }{2}$

your answer is a

What is the solution to this equation? x^2+3x+7=0

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