Rosetta wants to write equations in the form y=mx+b for the lines passing through point p that are parallel and perpendicular to line g. first she finds the slopes of these two lines. what could she do next to find the y-intercepts?

a. substitute the slope and the coordinates of point p in y=mx+b and then solve for b for each equation.
b. multiply the slope by the x-coordinate and add the y-coordinate to the product.
c. multiply the slope by the y-coordinate and subtract the result from the x-coordinate.
d. solve the proportion m/b=y/x for b.

A. Substitute the slope and the coordinates of point P in y=mx+b and then solve for b for each equation.

Step-by-step explanation:

We know the equation for a line passing through a point P(x,y) is given as:

y = mx + b

where

m is the slope of the line.

x, y are the co-ordinates of point P.

b is the y-intercept of line on point P(x,y).

If g is the line. we find its slop m. Let's the slope 'm' is given as m = b/a

The slope of lines parallel to line g is b/a.

The slope of lines perpendicular to line g is -a/b.

Substituting the slope and and coordinates of point P and then solving for b will give us the y-intercept.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .