Ab and ac are tangent segments of circle k(o). what is the measure of the angle ∠bac, if midpoint of ao lies on the circle k(o)?
m∠bac=

  60°

Step-by-step explanation:

B and C are the points of intersection of the circle with diameter AO with circle O. If the midpoint of AO is X on circle O, then XO = XB = XC and ΔXOB and ΔXOC are equilateral triangles. That makes ∠BOC = 120° and its supplement, ∠BAC, equal to 60°.

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hard

step-by-step explanation: