There are 38 students. if there are 6 seats at each table, how many tables would be needed for all of the students to be able to sit at a table?

7 tables

Step-by-step explanation:

So if 6 students can fit at each table, you divide 38 by 6. You get 6 1/3 ,but since you can't get 1/3 of a table, you have to get 7

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).