In parallelogram abcd point k belongs to diagonal
bd
and divides
bd
so that bk: dk=1: 4. if ray
ak
meets
bc
at point e, what is the ratio of be: ec?

Step-by-step explanation:

Consider triangles BKE and DKA. In this triangles:

Thus triangles BKE and DKA are similar by AA theorem. Similar triangles have proportional sides lengths:

Thus,

Since AD=BC and BC=BE+CE, we have that 4BE=BE+EC, EC=3BE. Hence, the ratio BE to EC is

answer: kljdcdhjbdlchjad oac apoich a

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %