Astudy was conducted on the weights of newborn piglets. the weights were normally distributed with a mean μ = 0.76 kg and standard deviation σ = 0.18 kg. if the study involved 5,000 piglets, how many of them weighed more than 0.94 kg? a. 800 b. 600 c. 2500 d. 4200

A. 800

Step-by-step explanation:

Let the random variable X denote the weight of newborn piglets. We first determine the probability that X is greater than 0.94;

Pr( X>0.94)

We apply the standard normal transformation;

Z = (X-μ)/σ

Pr( X>0.94) = Pr( Z>(0.94-0.76)/0.18)

                   = Pr( Z>1)

                   = 0.1587, from the standard normal tables

To determine the number that weighed more than 0.94 kg, we simply multiply this probability with the number 5000;

5000*0.1587 = 793.5 which is close to 800

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.