Asap! first answer will be marked as brainliest. work attached.

14) <CBE = 118°

15) <ABF = 28°

16) <CBA = 152°

17) <B = 18° and <A = 72°

18) <E = 30° and <D = 150°

Step-by-step explanation:

14)

<CBE = 180 - <EBF = 180 - 62 = 118°

15)

<ABF = 90 - <EFB = 90 - 62 = 28°

16)

<CBA = 180 - <ABF = 180 - 28 = 152°

17)

<A = 4 <B

<A + <B = 90° (sum of complementary angles) so <A = 90 - <B

Substitute <A = 90 - <B into <A = 4 <B

90 - <B = 4 <B

90 = 4 <B + <B

90 = 5<B

<B = 90/5

<B = 18°

<A = 90 - 18° = 72°

18)

<D = 5 <E

<D + <E = 180° (sum of complementary angles) so <D = 180 - <E

Substitute < <D = 180 - <E  into <D = 5 <E

180 - <E = 5 <E

180 = 5 <E + <E

180 = 6 <E

<E = 180/6

<E = 30°

<D = 180 - 30° = 150°

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length