Find the eight term of a geometric sequence for which a3=35 and r=7

588245.

Step-by-step explanation:

nth term = an = a1 r^(n-1)   where a1 = the first term

a3 = 35 = a1  7^(3 - 1)

35 = a1* 49

a1 = 35/49 = 5/7

So the 8th term = (5/7)* (7)^7

= 588245

18a

step-by-step explanation:

simply because it is. it's the highest common factor

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225