The theme park company is building a scale model of the killer whale stadium main show tank for an investor's presentation. each dimension will be made 6 times smaller to accommodate the mock-up in the presentation room. how many times smaller than the actual volume is the volume of the mock-up?

using the information from the question above, answer the following question by filling in the blank: the volume of the actual tank is % of the mock-up of the tank.

Since

the mock up is 6 times smaller than the actual killer whale stadium, then the

radius of the mock up would be:

radius

mock up = 70 / 6 = 11.67

Therefore

the volume of the mock up would be one fourth of the volume of a sphere since the

shape is like one fourth of a sphere.

V mock

up = ¼ * Volume of sphere

V mock

up = ¼ * 4/3 * pi * r^3

V mock

up = 0.25 * 4/3 * pi * 11.67^3

V mock

up = 1664.34

Therefore

the ratio is

Actual

volume / V mock up = 359007 / 1664.34 = 215.7

Therefore the mock up is about 216 times smaller than the

actual stadium.

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│Hope this helped  │    

│~Derelis │

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d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

because its not ur topic and its not for is for homework not that.