Determine e, k, and identify the type of conic for r =3/2-6 cos theta.

The answer is (c) ⇒ e = 3 and k = 1/2 , conic: hyperbola

Step-by-step explanation:

∵ r = ek/(1 ± ecosФ)

∵ r = 3/(2 - 6cosФ) ⇒ ÷ 2 up and down

∴ r = (3/2)/(1 - 3cosФ)

∴ e = 3

∵ ek = 3/2 ⇒ 3k = 3/2

∴ k = 1/2

∵ e > 1

∴ The conic is hyperbola

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: