Abasketball player makes 8 of 22 shots in game 1, 6 of 15 shots in game 2, and 10 of 23 shots in game 3. what percent of the shots did the player make in the three games?

40%

Step-by-step explanation:

To find the percentage in each game, you divide the number of successful shots by the number of total shots. For game 1, this looks like: 8/22 = 0.3636, or 36%.

For game 2, this give us 40%, and for game 3, 43%.

Not sure if the question is asking for a game-by-game answer or a grand total, so we'll do both. To find the total percentage over the course of the games, add all the successful shots (8 + 6 + 10 = 24) and all the attempted shots (22 + 15 + 23 = 60), and divide the same way (24 / 60 = 40%).

i know the answer is 3

step-by-step explanation: