Parallelogram abcd has vertices at a(0, 0) , b(4, 5) , c(8, 0) , and d(4,−5) .

which conclusion can be made?

1. ab⊥bc ; therefore, abcd is a square.

2. ab⊥bc ; therefore, abcd is a rectangle.

3. ab=bc ; therefore abcd is a square.

4. ab=bc ; therefore, abcd is a rhombus.

AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41

BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41

CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41

AD = √(-5-0)^2 + (4-0)^2 = √25+16  = √41

All the sides are equal so it is either a square or a rhombus.

The distance from A to C  on the x axis is: 8-0 =  8 units.

The distance from B to D on the Y axis is: 5 - - 5 = 10 units.

Because the two distances are not the same, it is not a square.

The answer is 4. AB=BC ; therefore, ABCD is a rhombus.