Find the exact value of sine, cosine, and tangent of a and t for each triangle.

See below  

Step-by-step explanation:

7)

AT² = 11² + 4² = 121 + 16 = 137

AT = √137

sinA = DT/AT = 11/√137 = (11√137)/137

cosA = AD/AT = 4/√137 = (4√137)/137

tanA = DT/AD                 = 11/4

sinT = AD/AT = 4/√137 = (4√137)/137

cosT = DT/AT = 11/√137 = (11√137)/137

tanT = AD/DT                 = 4/11

9)

AT² = 8² + 3² = 64 + 9 = 73

AT = √73

sinA = LT/AT = 8/√73 = (8√73)/73

cosA = AL/AT = 3/√73 = (3√73)/73

tanA = LT/AL                = 8/3

sinT = AL/AT = 3/√73 = (3√73)/73

cosT = LT/AT = 8/√73 = (8√73)/73

tanT = AL/LT                = 3/8

11)

    6² =  4² + RT²

  36 = 16  + RT²

RT² = 20

RT =√20 = √(4× 5) = 2√5

 sinA = RT/AT = (2√5)/6 = (√5)/3

cosA = AR/AT = 4/6        = 2/3

tanA = RT/AR = (2√5)/4 = (√5)/2

 sinT = AR/AT = 4/6        = 2/3

cosT = RT/AT = (2√5)/6 = (√5)/3

tanT = AR/RT = 4/(2√5)  = (2√5)/5

answer:      

step-by-step explanation: