nevin started a geometric sequence. the first four terms of his sequence are show below.
162,54,18,6, . .
3.) what is the sixth therm of nevin sequence? show or explain how you got the answer.
4.) write an expression that represents the ᵗʰ term of nevin sequence.

3) 2/3

4) an = 162·(1/3)^(n-1)

Step-by-step explanation:

3) A geometric sequence has a common ratio between adjacent terms. Here, that ratio is ...

r = 54/162 = 18/54 = 6/18 = 1/3

Then the next two terms can be found by multiplying by the common ratio:

6 · 1/3 = 2

2 · 1/3 = 2/3 . . . . . the sixth term

4) The generic expression for the n-th term of a geometric sequence with first term a1 and common ratio r is ...

an = a1·r^(n-1)

We can put in the numbers for a1 and r, and we have ...

an = 162·(1/3)^(n-1)

9 x 8 divided by (5-3)=36

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: