Points a and b split the circle into two arcs. measure of minor arc is 150°. point m splits major arc with the ratio 2: 5 (point m is closer to point b). find m? bam.

∠BAM=30°

Step-by-step explanation:

Points A and B split the circle into two arcs. If the measure of minor arc AB is 150°, then the measure of the major arc AB is 360°-150°=210°.

If point M splits major arc with the ratio 2:5, then

Angles BOM and AOM together form angle with the measure 210°, thus

2x+5x=210,

7x=210,

x=30°

and ∠BOM=60°, ∠AOM=150°.

Consider isosceles triangle BOM. In this triangle,

∠OBM=1/2(180°-60°)=60°.

Consider isosceles triangle AOB. In this triangle,

∠OAB=1/2(180°-150°)=15°.

Consider isosceles triangle AOM. In this triangle,

∠OAM=1/2(180°-150°)=15°.

Thus, ∠BAM=15°+15°=30°

arc BAM =  300°

Step-by-step explanation:

Refer to the figure attached.

arc AB = 150°

then:

arc AMB = 360° - 150° = 210°

arc AMB can be decomposed as:  

arc AM + arc MB = arc AMB (eq. 1)

From data:

arc MB/arc AM = 2/5

arc MB*(5/2) = arc AM (eq. 2)

Replacing equation 2 into equation 1:

arc MB*(5/2) + arc MB = 210°

arc MB*(7/2) =  210°

arc MB = (2/7)*210° = 60°

On the other hand:

arc MB + arc BAM = 360°

arc BAM = 360° - 60° =  300°

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step-by-step explanation: