Ahelicopter flying 1600 feet above ground spots an airplane flying above. if the horizontal distance between the helicopter and airplane is 3,055 feet and angle of elevation is 71 degrees, find the airplane’s altitude.

10,472.36 feet

Step-by-step explanation:

- Observe the diagram attached (It is not drawn to scale).

- Calculate the height between helicopter and airplane (h), as following:

Solve for h:

- Therefore, the altitude of the plane is:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

jml angle lkj & angle mj = lm