What are the zeros of g(x)=(3x-1)(2x+5)(7x-14)^2
answer asap by the end of the day with the work. plz!

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(3x - 1)(2x + 5)(7x - 14)² = 0

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x =

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = -

(7x - 14 )²  = 0 ⇒ 7x - 14 = 0 ⇒ x = 2 with multiplicity 2

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.