Iwill award ! ! solve for

using the given equation find the missing coordinates of the points and then find the slope of the line for each equation

1) y−2x=3; ; 6), b(15;

2) 4.5x+3y=2; ; 1/3 ), b( 2/3 ;

1. A(3/2,6)

B(15,33)

2.A(2/9,1/3)

B(2/3,-1/3)

Step-by-step explanation:

1) y−2x=3; A(...; 6), B(15; ...)

We know y =6

Substitute this into the equation

6 -2x =3

Subtract 6 from each side

6-6 -2x=3-6

-2x = -3

Divide by -2

x = -3/-2

x = 3/2

A(3/2,6)

We know x = 15

y - 2(15) =3

y - 30 = 3

Add 30 to each side

y-30+30 = 3+30

y = 33

B(15,33)

2) 4.5x+3y=2; A(...; 1/3 ), B( 2/3 ; ...)

We know y = 1/3

4.5x + 3(1/3) = 2

4.5x +1 =2

Subtract 1 from each side

4.5x +1-1=2-1

4.5x = 1

Divide each side by 4.5

x = 1/4.5

x = 10/45

x =2/9

A(2/9,1/3)

Let x =2/3

4.5(2/3) +3y =2

3 +3y =2

Subtract 3 from each side

3-3+3y = 2-3

3y = -1

Divide by 3

y = -1/3

B(2/3,-1/3)

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23