In 2005 there were 14000 students at college a, with a projected enrollment increase of 750 students per year. in the same year there were 35000 students at college b with a projected enrollment decline of 1000 students per year. according to these projectors when will the colleges have the same enrollment? what will be the enrollment in each college at that time

 in 12 years (2017)

               23,000 students enrolled

Step-by-step explanation:

Let x represent the number of years since 2005.

Let y represent the number of students enrolled.

College A: y = 14,000 + 750x

College B: y = 35,000 - 1000x

Solve the system using the Substitution Method:

14,000 + 750x = 35,000 - 1000x

           +1000x               +1000x

14,000  + 1750x = 35,000

-14,000                 -14,000

                1750x = 21,000

                        x = 12

Input x = 12 into one of the equations to solve for y.

y = 35,000 - 1000x

  = 35,000 - 1000(12)

  = 35,000 - 12,000

  = 23,000

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.