Abag contains 5 red balls, 3 green balls, and 2 yellow balls. find the sum of the probability of drawing a red ball, replacing it, drawing a green ball, replacing it and drawing a yellow ball.

Red - 5/10

Green - 3/10

Yellow 2/10

Easyyy

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➷ You replace the balls, so the type of probability is independent.

First of all, the probability of getting a red ball is:

5/10 or 1/2

As you can see, the probability of getting a green ball is:

3/10

Lastly, the probability of getting a yellow ball is:

2/10 or 1/5

The sum of all of them added together is always:

10/10, or 1

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬TROLLER (don't worry i didn't troll you)

answer: 7270

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.