Which pair of the following straight lines are parallel and how?
a. 2x + y + 1 = 0
b. y = 3x - 1
c. 2x - y = 3
d. y = 4x + 3
e. y = x/2 - 1
f. 6x - 2y = 0
g. 3y = x + 4
h. 2y = 5 - x

f and b

Step-by-step explanation:

if you put them in y-intercept form, both slopes are 3

In b. it's easy to see that 3x has a slope of 3.

In f. it's not so obvious. Just solve for y or use the shortcut m = -a/b where a is the coefficient of x and  b is the coeff of y.

hence -(6/-2)=3

Step-by-step explanation:

assuming you know how to put the equations into y = m x + b already.  All equations have to be put in that format to identify the slope.  Parallel lines have the same slope.

a.  y = -2x - 1; slope -2

b.  y = 3x - 1; slope 3

c.  y = 2x - 3; slope 2

d.  y = 4x + 3; slope 4

e.  y = x/2 - 1; slope 1/2

f.  y = 3x; slope 3

g.  y = x/3 + 4/3; slope 1/3

h.  y = -x/2 + 5; slope -1/2

There are only 2 that are alike.  b and f both have a slope of 3.  all the other slopes are different.

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm