Two automobiles left simultaneously from cities a and b heading towards each other and met in 5 hours. the speed of the automobile that left city a was 10 km/hour less than the speed of the other automobile. if the first automobile had left city a 4.5 hours earlier than the other automobile left city b, then the two would have met 150 km away from b. find the distance between a and b.

The distance between the two is:

d=1600km

Hope this helps! :)

Step-by-step explanation:

so, we know A and B left at the same time, one from city A and the other from city B, they're both moving towards each other, and they met in 5hrs.

now, by the time they met, car A has been running for 5hrs already,

and car B has also been running for 5hrs, so the time for both is the same, when they met, each had been running for 5hrs

if B has a speed rate of "r", then A's speed rate is " r - 10"

now, the next to last paragraph

"If the first automobile had left city A 4 1/2 hours earlier than the other automobile left city B, then the two would have met 150 km away from B."

IF, a big if, but they didn't, they left at the same exact time, so that's just an IF

if A had left 4 1/2 hrs earlier, they'd had met 150km from B

so... by the time A had been running already for 4.5 hrs, car B starts off, goes off and they meet 5hrs later, when they meet, car A would have been running for 5hrs, 4.5 + .5 hrs, but car B would had been running for only half an hour when they met

that means car B met car A half an hour later from when it started, and met A 150kms away from its starting point

that means car B can cover 150km in just half an hour

that gives us a speed rate of 150/.5  

which is 300kmh

now, if car B is 300kmh, car A has r-10, or 300-10, or 290kmh

so, car A's rate is really just 290

now, let's say the total distance is AB

so, by the time car A had been running for 5hrs, it had covered a distance of "d"

by the time car B had been running for 5hrs, it had then covered the slack, or " AB - d "

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: