The vertex form of the equation of
a parabola is y = 2(x +4)^2 - 7.what is the standard form of the equation?

The standard form of the equation is y = 2x^2 + 16x + 25

Step-by-step explanation:

To find the standard form, first square the parenthesis.

y = 2(x + 4)^2 - 7

y = 2(x^2 + -8x + 16) - 7

Now distribute the 2

y = 2(x^2 + 8x + 16) - 7

y = 2x^2 + 16x + 32 - 7

Now combine like terms

y = 2x^2 + 16x + 32 - 7

y = 2x^2 + 16x + 25

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: