In △xyz , xy=xz . find the perimeter of △xyz if xy=2a , yz=3a+1 , and xz=5a−12 .

Perimeter = 10a - 11

Step-by-step explanation:

In triangle XYZ, the 3 sides are XY, YZ, and XZ.

The perimeter of a triangle is sum of the 3 sides.

For this problem, the perimeter = XY + YZ + XZ

Putting in the information given, we get:

Perimeter = 2a + (3a+1) + (5a-12)

Adding like terms, we get:

= 2a + 3a + 1 + 5a - 12

= 10a - 11

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)