Which polynomial function has a leading coefficient of 1, roots –2 and 7 with multiplicity 1, and root 5 with multiplicity 2?

f(x) = 2(x + 7)(x + 5)(x – 2)

f(x) = 2(x – 7)(x – 5)(x + 2)

f(x) = (x + 7)(x + 5)(x + 5)(x – 2)

f(x) = (x – 7)(x – 5)(x – 5)(x + 2)

ANSWER

EXPLANATION

If the polynomial has a root -2, with multiplicity 1, then (x+2) is a factor.

If the polynomial has root, 7 with multiplicity 1, then (x-7) is a factor.

If the polynomial has root 5, with multiplicity 2, then (x-5)² is a factor of the polynomial.

The fully factored form of the polynomial is

It was given that the polynomial has a leading coefficient of 1.

Hence a=1.

This implies that,

Or

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

henry ordered 5 large pizzas

step-by-step explanation:

sorry no step by step