given: m ab =32°, ac ≅bc, tangent as

find: m∠cao, m∠sac

m∠CAO=8º

m∠SAC=82º

Step-by-step explanation:

We know that m∠OAS is 90º because it is a radius to a tangent. This will be useful later.

OA=OB because they are both radii. If we draw a line from A to B, this makes an isosceles triangle ABO with a vertex angle of 32 because of the central angle theorem. This means that m∠OAB and m∠OBA are both 74º.

Isosceles triangle CAB is also formed with the construction of AB. Using the inscribed angle theorem, we can find ACB, which is 16º. Solve for the other angles and you get 82º. To find m∠CAO, subtract m∠OAB from m∠CAB, and this returns 8.

To find m∠SAC, subtract m∠CAO from m∠OAS, which is 90º-8º, and you get 82º.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).