Factor x^3 -4x^2 -3x +18 =0
given that 4 is a zero

a (x-2) (x-3) (x+3)=0
b (x-2) (x-3)^2 =0
c (x-2) (x- sqrt 3)(x+ sqrt 3) =0
d (x-2) (x-3)^2 =0

none of the above

Step-by-step explanation:

A graphing calculator shows the zeros to be x=-2, and a double zero at x=3. Hence the factorization is ...

(x +2)(x -3)^2 = 0

The premise that 4 is a zero is incorrect, and none of the answer choices include (x+2) as a factor. The problem is unworkable as written here.