![\sqrt[3]{-56ab^6c^{10}}=\sqrt[3]{-56}\cdot\sqrt[3]{a}\cdot\sqrt[3]{b^6}\cdot\sqrt[3]{c^10}](/tpl/images/0501/0666/1d328.png)
![\sqrt[3]{-56} = -\sqrt[3]{2^3\cdot 7} = -\sqrt[3]{2^3}\cdot\sqrt[3]{7} = -2\sqrt[3]{7}](/tpl/images/0501/0666/571c8.png)
![\sqrt[3]{a}](/tpl/images/0501/0666/26893.png)
, because the exponent is lower than the order of the root.![\sqrt[3]{b^6} = (b^6)^{\frac{1}{3}} = b^\frac{6}{3}=b^2](/tpl/images/0501/0666/b4609.png)
![\sqrt[3]{c^{10}} =\sqrt[3]{c^{9+1}}=\sqrt[3]{c^{9}\cdot c}=c^\frac{9}{3}\cdot\sqrt[3]{c}=c^3\sqrt[3]{c}](/tpl/images/0501/0666/e4f25.png)
![-2b^2c^3\sqrt[3]{7ac}](/tpl/images/0501/0666/ae03a.png)
Can you solve this by simplifying the radical?
...
Answers: 3
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