Find the area of an equilateral triangle with a side of 6 inches

15.59 inches²

Step-by-step explanation:

Area of a triangle = (base) × (height)

Base of the triangle = 6 inches = BC

so BD = CD = 3 inches

Now height h = AD = [ By Pythagoras theorem ]

h =

=

=

Now area of equilateral triangle ABC

=  (6) ( )

= 3 ×  ()

=   inches²

≈ 15.59 inches²

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465