Select the correct answer from each drop-down menu. ∆abc has a(-3, 6), b(2, 1), and c(9, 5) as its vertices. the length of side ab is units. the length of side bc is units. the length of side ac is units. ∠abc ≈ °.

√50

√65

√145

105 °

Step-by-step explanation:

Given the coordinates

A(-3, 6)

B(2, 1)

C(9, 5)

To find the length of AB ,AC and BC, we will use distance formula

AB:

√(2+3)² + (1-6)²

√5²+5²

√50

BC:

√(9-2)² + (5-1)²

√7² + 4²

√49+16

√65

AC:

√(9+3)² + (5-6)²

√12²+1²

√145

To find ∠ABC

cos(B) =  c² + a² − b² / 2ca

          =  65 + 50 - 145 / 2(√65)(√50)

cosB   = -0.26311

B         = cos^-1(-0.26311)

          = 105 °

found it xd it ok yt