Etermine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 3 2 x − 2y = 4 x + 1 3 y = 2 one and only one solution infinitely many solutions no solution find the solution, if one exists. (if there are infinitely many solutions, express x and y in terms of the parameter t. if there is no solution, enter no solution.) (x, y) =

(32/15, -2/5)

Step-by-step explanation:

(1) ³/₂x   -    2y =  4

(2)   x  +    ⅓y =  2

(3)  3x   -     4y =  8              Multiplied (1) by 2

(4)  3x  +       y =  6              Multiplied (2) by 3

                  5y = -2              Subtracted (3) from (4)

(5)                 y = -⅖             Divided each side by 5

       x + ⅓(-⅖) =  2              Substituted (5) into (2)

       x  -  ²/₁₅    =  2

       x              =  2 + ²/₁₅     Added ²/₁₅ to each side

      x              = 32/15

The system of equations has only one solution: (32/15, -2/5).