Given: circle k(o), dc ∥ ab , ac ∩ db =0, m ad =124°find: m∠c, m∠aob.

Part 1) The measure of angle C is

Part 2) The measure of angle AOB is

Step-by-step explanation:

step 1

Find the measure of angle C

we know that

The inscribed angle measures half that of the arc comprising

so

we have

substitute

step 2

Find the measure of angle AOB

we know that

In the isosceles triangle  ODC

∠D=∠C=62°

Remember that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

∠D+∠C+∠DOC=180°

substitute the values

62°+62°+∠DOC=180°

∠DOC=180°-124°=56°

we have that

∠AOB=∠DOC -----> by vertical angles

so

∠AOB=56°

its a i did it myself

step-by-step explanation:

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder