Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), or neither (if the set is not a relation). input -1 0 -1 -8 9 output 0 1 2 4 8 function relation neither

Relation.

Step-by-step explanation:

This is a relation but not a function. The input -1 maps to both 0 and 2; this is a one-to-many relation  so it is not a function. Functions are either one-to-one or many-to-one.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its an acute right triangle

step-by-step explanation: