What is the equation of the line that has a slope of 0 and passes through the point (6,-8)

Hello there!

we want to find the equation that passes through the point (6, -8) (where this notation stands for (x,y)) with a slope of 0.

a linear equation has the form y = ax+ b

where a is the slope and b is the intercept.

if a = 0, our equation has the form y = b (has no dependence of x)

so we have a constant equation that passes through the point (6, -8) , this means x = 6 and y = -8, but we know that y is constant:

then y = -8 = b

so our equation is y(x) = -8

i just took the test, the correct answer is .. 31.5 in.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: