If y=x-6 where changed to y=x+8 how would the graph of the new function compare with the first one ?

The function is the function shifted 14 units up.

The graph of the first equation will be a line with slope 1 that intersects the y-axis at point (0,-6)

The graph of the second equation will be a line with slope 1 that intersects the y-axis at point (0,8)

Step-by-step explanation:

The equation of the line in slope intercept form is:

Where m is the slope and b is the y-intercept.

The first equation is:

The second equation is:

The parent function with the form can be shifted up or shifted down k units.

When the function is shifted k units up.

When the function is shifted k units down.

Then, the function is obtained by adding k=14 to the function .

Both equation has the same slope, but the y-intercepts are different.

The graph of the first equation will be a line with slope 1 that intersects the y-axis at point (0,-6)

The graph of the second equation will be a line with slope 1 that intersects the y-axis at point (0,8)

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1