Ajar contains 4 red marbles, 4 green marbles, and 5 blue marbles.
if we choose a marble, then another marble without putting the first one back in the jar, what is the probability that the first marble will be blue and the second will be green?

20/156 or 5/39

Step-by-step explanation:

the first part of the equation will be:

5/13 (5 is how many blue and 13 is altogether)

the next part of this equation is the green marble. Because we didn't put the blue marble back, the next part of the equation will be:

4/12 (4 is how many green and 12 is altogether now that one blue was taken out)

and from there, you multiply 5/13 with 4/12, with will give you 20/156, or 5/39 if you simplify.

On khan it is 5/39

Step-by-step explanation:

just got it right lol

answer:   14

step-by-step explanation:          

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solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.