Rewrite the quadratic function in vertex form.
y=5x^2-10x+2

y = 5x2 + 10x - 15

We want this in format y = a(x-h)2 + k

where the vertex will be at (h,k)

y = 5(x2+2x) - 15

Complete the square on x2+2x

y = 5(x2+2x+1) - 15 - 5

We subtract 5 at the end because we are actually adding 5(1) = 5

so we need to remove it also to keep the total equal

y = 5(x+1)2 - 20

The vertex is at (-1,-20)

addition

step-by-step explanation:

it is x equals 3   plese mark me really need it

step-by-step explanation: