Mathematics, 20.08.2019 18:30 jrjordans13ox06qs
How do you find the derivative of y=ln(cos(x))y=ln(cos(x)) ?
Answers: 3
![y=ln(cosx)\\\\We\ know:\\(lnx)'=\frac{1}{x}\ and\ (cosx)'=-sinx\ and\ \{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\\\therefore:\\\\y'=\frac{1}{cosx}\cdot(-sinx)=-\frac{sinx}{cosx}=-tanx](/tpl/images/0182/3665/b3fd6.png)
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