Given: tsr and qrs are right angles; t ≅ q

prove: tsr ≅ qrs

step 1: we know that tsr ≅ qrs because all right angles are congruent.

step 2: we know that t ≅ q because it is given.

step 3: we know that sr ≅ rs because of the reflexive property.

step 4: tsr ≅ qrs because

1. of the asa congruence theorem

2. of the aas congruence theorem

3. of the third angel theorem

4. all right triangles are congruent

The answer is number (2) ⇒ because of the AAS congruence theorem

Step-by-step explanation:

* Lets use the information to solve the problem

- In the given triangles TSR and QRS

# We have a common side RS or SR

# Two right angles TSR and QRS

# m∠T = m∠Q ⇒ given

* So we have two pairs of angles and one common side, lets

 revise the cases of congruence

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

 including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

 ≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

* Now lets read the statements and write the missing

Step 1: m∠TSR = m∠QRS = 90° ⇒ because all right angles are congruent

Step 2: m∠T = m∠Q ⇒ because it is given

Step 3: SR ≅ RS ⇒ because of reflexive property (common side)

Step 4: Δ TSR ≅ ΔQRS ⇒ because of the AAS congruence theorem  

* The answer is number (2)

2nd one in the first row is correct

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl