The sum of four consecutive integers is 18 find the largest consecutive integer

The largest consecutive integer is 6

Step-by-step explanation:

Let n, n +1, n+2, and n+3 are the  four consecutive integers

The sum of four consecutive integers is 18

n + n + 1 + n + 2 + n + 3 = 18

4n + 6 = 18

4n = 12

n = 3

The sum of four consecutive integers: 3, 4 , 5 , 6

The largest consecutive integer is 6

The sum of 3 consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

X + 3 → fourth integer

Since the sum of our three consecutive integers is 18, our equation will read...

X + X + 1 + X + 2 + X + 3 = 18

If we simplify on the left, our equation will read

X + 3 = largest integer

3 = 3 = 6

Therefore, the largest integer is 6.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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