Identify the equation in point slope form for the line perpendicular to y=3x+5that passes through (4,-1).

For this case we have that by definition, if two lines are perpendicular, then it follows that:

We have

So:

Thus, the equation would be:

We have the point:

We replace:

Option C

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐