By accident, 6 burned out bulbs have additionally been mixed in with 28 good ones. ken is replacing old bulbs in his house. if he selects two bulbs at random from the box of 34, what is the probability they both work?

p(both work) = 196 / 289

p(both work) = 5 / 187

p(both work) = 325 / 512

p(both work) = 126 / 187

P(Both work) = 126/187

Step-by-step explanation:

Number of burned out bulbs = 6

Number of good ones = 28

Therefore;

P( Not working bulb) = 6/34

P (working bulb) = 28/34

Therefore;

Probability of choosing a working bulb the first time = 28/34

Probability of choosing a working bulb the second time = 27/33

Hence;

P(Both work) = 28/34 × 27/33

                     = 126/187

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

something over 10 so ? /10

step-by-step explanation: