Undergraduate enrollment at elite university was 3,430 students in 2010. in 2015, enrollment was 3630. what would the slope of the graph of the linear equation that models this enrollment growth be(in students per year)?

40 students/yr

Step-by-step explanation:

The formula for the slope m of a straight line is  

m = Δy/Δx = (y₂ -y₁)/(x₂ - x₁)

We have two points on the line: (2010, 3430) and (2015, 3630). Then ,

m = (3630 - 3430)/(2015 - 2010) = 200/5 = 40 students/yr

In other words, the enrolment increases by 40 students each year.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."